Question

A bullet of mass 50kg is moving with a velocity of 500m/s.It penetrates 10cm into a still target and vomes to rest.Calculate(i)the kinetic energy possed by the bullet,and(ii)the acerage retarding force offered by the target.​

Answer 1

Answer

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Answer 2

Mass (m) = 50 g = 50 × 10-3 kg

Initial velocity (u) = 500 ms⁻¹

Distance (s) = 10 cm = 10 × 10⁻² m

Final velocity (v) = 0

(i) KE = 1/2 mv² = 1/2 × 50 × 10⁻³ × (500)² = 6250 J

(ii) Using v² - u² = 2as : 

a = {v² - u²} / {2s} = {0 - (500)²} / {2 × 10 × 10⁻²} 

= 1250000 ms⁻²

Therefore, retarding force, F = ma = 50 × 10⁻³ × 1250000 = 62500 N