Math, asked by sushilgurawti4583, 1 year ago

The cost of flooring a rectangular Hall at rupees 64 per square metre is rupees 2048 full stop if the breadth of the hall is 5 metre, find its length, its perimeter, cost of fixing a border of very small with along its boundary at the rate of
60 rupees per metre

Answers

Answered by Anonymous
6

Answer:

Step-by-step explanation:

cost of flooring=Rs 2048

Rate=Rs 64/ sq m

Hence area= cost/rate=2048/64=32 sq m

breadth= 5 m

length= area/ breadth

length=32/5=6.4 m

Therefore perimeter=2*(length+breadth)

=2*(6.4+5)=2*11.4

perimeter=22.8 meter

Cost of border

=60*perimeter

=60*22.8=Rs 1368

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