A bullet of mass 5g travelling at a speed of 120ms penetrates deeply into fixed target and is brought to rest in 0.01s. Calculate i) the distance in of penetration in the target, ii) the average force exerted on the bullet.
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heyy user ur answer............
u = 120 m/s
v = 0
t = 0.01 s
a = (v-u)/ t = -120 / 0.01 = -12000 m/s
a) S = (v² - u²)/2a = -120² / 2*(-12000) = 120 / 200 = 0.6 m
distance of penetration is 0.6m
b) force = ma = 0.005×12000 = 60N..........hope this will help u....@kundan
u = 120 m/s
v = 0
t = 0.01 s
a = (v-u)/ t = -120 / 0.01 = -12000 m/s
a) S = (v² - u²)/2a = -120² / 2*(-12000) = 120 / 200 = 0.6 m
distance of penetration is 0.6m
b) force = ma = 0.005×12000 = 60N..........hope this will help u....@kundan
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