Question

how many g of element are present are in 35.125g atom of Si.

Answer 1

mass of 1 silicon atom=28 g 
mass of 35.125 g of silicon atom= 35.125x28
                                                    =983.5 grams

Answer 2

Answer : 983.5 g of element are present in 35.125 g atom of Si.

Solution : Given,

Mass of Si = 35.125 g atom

Molar mass of Si = 28 g/mole

As we know that, one mole is equal to the one gram atom which is also equal to the molar mass.

1 mole = 1 g atom = Molar mass

As per question,

1 gram atom of silicon weigh = 28 g

35.125 gram of silicon weigh = 35.125 × 28 = 983.5 g

Therefore, 983.5 g of element are present in 35.125 g atom of Si.