Question

A bullet of mass m is fired from below into a bob of mass M of a long simple pendulum. The bullet stays inside the bob and the bob rises to a height h. The initial speed of the bullet will be

Answer 1

yaar below means what......
From below we can fire it from an angle also or we can fire it just standing down ........?
please clarify the question.

Answer 2

Answer:

Explanation:

Let the common velocity of bullet and bob be v after the bullet is embedded. Applying the law of conservation of momentum, we have (M+m)v=mu (u = initial speed of bullet)

After this, the motion of bob is controlled by gravity v=√2gh

∴so putting the values

√2gh(M+m)=mu

so, u=$\sqrt{2gh} \frac{M+m}m}$