Question

A bullet of mass m is fired with velocity Q in a large body of mass R the final velocity of the system will be

Answer 1

Let the final velocity of the system is V.

By using the conservation of momentum, we can calculate the final velocity of the system.

$V = \frac{m_{1}v_{1} +m_{2}v_{2}   }{m_{1}+m_{2}  }$

Considering that the bullets get embedded into the large block

As given the initial velocity $v_{1} =Q$  and mass of bullet $m_{1} = m$  and mass of large body is $m_{1} =R$ and $v_{2} = 0$.

Therefore, by conservation of momentum,

$V = \frac{m \timesQ + R\times0}{m+R }$

so final velocity,

$V = \frac{mQ}{m+R}$ 

Answer 2

Answer:

Considering that the bullets get embedded into the large block

As given the initial velocity v_{1} =Qv

1

=Q and mass of bullet m_{1} = mm

1

=m and mass of large body is m_{1} =Rm

1

=R and v_{2} = 0v

2

=0 .

Therefore, by conservation of momentum,

so final velocity,

V = \frac{mQ}{m+R}V=

m+R

mQ

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