Question

A bullet of mass m, moving horizontally with velocity v hits and gets embedded in a wooden block of mass M resting on a horizontal frictionless surface. What will be the velocity of this composite system?
(A) mv/(M - m)
(B) Mv/(M - m)
(C) Mv/(M + m)
(D) mv/(M + m)

Answer 1

Answer:

b option

Explanation:

Mv/(M-v)

i hope it helps

Answer 2

Answer:

(D) velocity of composite system = m.v/(M + m)

Explanation:

Given,

Mass of bullet = m

velocity of bullet = v

Mass of block = M

According to question,bullet of mass m, moving horizontally with velocity v hits and gets embedded in a wooden block of mass M resting on a horizontal friction less surface.

momentum of the bullet = m.v

mass of system after collision = M+ m

Let's consider velocity of composite system after collision is V, then according to  law of conservation of momentum

         initial momentum = final momentum

=>                       m.v = (M+m).V

=>                             V = m.v/(m+M)

So,  the velocity of this composite system after collision is  V = m.v/(m+M).