Physics, asked by Babukhuraw5910, 1 year ago

A force acts on an object of mass 1.5 kg at rest for 0.5 s. After the force stops acting, the object travels a distance of 5 m in 2 s. Hence the magnitude of the force will be ........................ .
(A) 5 N
(B) 7.5 N
(C) 10 N
(D) 12.5 N

Answers

Answered by ankitjain61
1

Answer:

We're asked to find the magnitude of the net force acting on the object.

We know:

initial velocity

v

0

x

=

0

(at rest)

mass

m

=

1.5

kg

time

t

=

0.5

s

final velocity

v

x

=

5

l

m

2

l

s

=

2.5

m/s

Let's use the kinematics equation

v

x

=

v

0

x

+

a

x

t

to find the acceleration. Plugging in known values, we have

2.5

l

m/s

=

0

+

a

x

(

0.5

l

s

)

a

x

=

5

m/s

2

The net force

F

on the object is thus

F

x

=

m

a

x

=

(

1.5

l

kg

)

(

5

l

m/s

2

)

=

7.5

N

Answered by deependra1806hu
1

Answer: 7.5N

Explanation:

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