A force acts on an object of mass 1.5 kg at rest for 0.5 s. After the force stops acting, the object travels a distance of 5 m in 2 s. Hence the magnitude of the force will be ........................ .
(A) 5 N
(B) 7.5 N
(C) 10 N
(D) 12.5 N
Answers
Answered by
1
Answer:
We're asked to find the magnitude of the net force acting on the object.
We know:
initial velocity
v
0
x
=
0
(at rest)
mass
m
=
1.5
kg
time
t
=
0.5
s
final velocity
v
x
=
5
l
m
2
l
s
=
2.5
m/s
Let's use the kinematics equation
v
x
=
v
0
x
+
a
x
t
to find the acceleration. Plugging in known values, we have
2.5
l
m/s
=
0
+
a
x
(
0.5
l
s
)
a
x
=
5
m/s
2
The net force
∑
F
on the object is thus
∑
F
x
=
m
a
x
=
(
1.5
l
kg
)
(
5
l
m/s
2
)
=
7.5
N
Answered by
1
Answer: 7.5N
Explanation:
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