a bullet of mass of 0.01kg fired from a gun hits a wooden plank witha a velocity 400 m/s and emerges out with a velocity 100m/s calculate the force by a plank to the motion of the bullet if the the thickness of the plank is 0.05m
Answers
Answered by
10
Answer:
Average resistive force is= mass (m) x a
=8000N
Step-by-step Explanation:
Initial velocity u =300m/s
Final velocity v= 100m/s
Distance s=0.05m
Retartdation be a
2xaxs= v²- u?
2xax0.05= 100x100 - 300x300
a= 800000
Average resistive force is= mass (m) x a
=8000N
Answered by
49
Given
- Mass(Bullet) = 0.01 Kg
- Initial Velocity = 400 m/s
- Final Velocity = 100 m/s
- Thickness (Plank) = 0.05 m
To Find
- Force applied by the plank
Solution
☯ v²-u² = 2as
- We shall use this third Equation of motion to find the acceleration of the body
☯ F = ma
- We shall us this formula to find the Force applied and hence the Answer!!
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✭ According to the Question :
→ v²-u² = 2as
→ 100²-400² = 2 × a × 0.05
→ 10000 - 160000 = 0.1a
→ -150000 = 0.1a
→ -150000/0.1 = a
→ Acceleration = -1500000 m/s²
━━━━━━━━━━━━━━━━━━━━━━━━━
✭ Force Applied :
→ F = ma
→ F = 0.01 × -1500000
→ F = -15000 N
- Note that the Force applied is negative as it is a force that is applied against the motion of the bullet
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