Question

a bullet of mass " penetates 10 cm into a mud wall. What is the average
9. A bullet of mass 30 g moving with a speed of 400 m s penetrates 10 cm into a mud wall. What is the ave
force exerted by the wall on the bullet?
(Ans. 24,000 N​

Answer 1

Answer:

Explanation:

Solution :-

Kinetic Energy of the bullet just before striking the wall is given by,

K.E = 1/2mv²

= 1/2 × (30 × 10⁻³) × 400²

= 1/2 × 3 × 10⁻² × 16 × 10⁴ J

= 2400 J ...(i)

The entire K.E is used in doing work against the average force exerted by the wall.

If F is the average force, we can write

work done, W = F × 10/100

W = 0.1 F .... (ii)

From Eq (i) and (ii), we get

0.1 F = 2400

or, F = 24000 N

Hence, the average force exerted by the wall is 24000 N.