Question

A bullet of mass X moves with a velocity y, hits a wooden block of mass z at rest and gets embedded in it After collision the wooden block and bullet moves with a velocity​

Answer 1

Explanation:

momentum of bullet before collision=Xy eq1

momentum of block before collision=0 eq2

let v be the velocity of bullet and block after collision

momentum of both the objects after collision (X+z)v eq3

using law of conservation of momentum

eq1+eq2=eq3

Xy+0=(X+z)v

v=Xy/X+z m/s