Physics, asked by shivanimaske5142, 1 year ago

A bullet shot underwater will experience "viscous drag" and follow this velocity equation:/

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Answered by ak1455988

0

Answer:

V_x(t) = V_ie^-bt Where V_i = 365 M/s And B = 0.42 S^-1. The Bullet Has An Initial Position X_i = 85.1 M At T_i = 0 S

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