Question

A bullet striking against a block of wood with a velocity of 360 m/s pierces a hole in it 12 cm deep. Calculate the deceleration of the bullet.
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Answer 1

Now ...

u=360m/s

V=0m/s

S=0.12m

Therefore=>

v^2 - u^2=2 a s

a= (v^2 - u^2)/2s

Put the values and solve further.

Answer will be => -540000 m/s^2

Answer 2

Explanation:

hope it helps....

Jai Shri Ram....