Question

A Bullet striking against a block of wood with a velocity of 360 metre per seconds pieces a 12 CM deep hole in it. calculate the deceleration of the bullet

Answer 1

Resistance offered-F=ma ,where m=100g=0.1kg accln is to be determined.v2=u2+asas bullet is stopped after 20 cm in plankv=0 ,u=20m/s ,s=20cm=0.2mOn substituting 02=202+2a*0.2a=-400/0.4a=-1000 (- sign represents deceleration)F=0.1*1000 (only magnitude of accln as we are not told to find F vector)F=100N=Resistance offered by wooden plank 

Answer 2

Answer:

-540000 m/s^2

Explanation:

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