Question

A bullet train start from rest and moves with unifrom acc 0.12m/s*2 find its final velocity and distance coverd after 5min​

Answer 1

Answer:

v = u + at

v = 0 + 0.12 x 5 x 60

v = 36 m/s

Answer 2

Answer:

It's final velocity and distance covered after 5 minutes is 36 m/s and 5400 m respectively.

Explanation:

Given:

• Acceleration (a) = 0.12 m/s.
• Time taken (t) = 5 minutes = 300 sec (since 1 min = 60 sec, 5 min = 5 × 60 = 300 sec)

To find:

Final velocity (v) and distance covered (s).

Solution:

We know that,

v = u + at

where v is final velocity;

u is initial velocity

a is acceleration and t is time.

By keeping the given values, we get

v = u + at

=> v = 0 + 0.12 × 300

=> v = 36 m/s.

Now distance, S = (u + v)/2 × t

= (0 + 36)/2 × 300 = 18 × 300

= 5400 m

Hence, v = 36 m/s and distance travelled = 5400 m.