a bullet travelling horizontally loosess 1/20th of its velocity while piercing a wooden plank number of such planks required to stop the bullet is
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S = (v^2 - u^2) / (2a)
v = u - u/20 = 19u/20
For one plank
S = ((19u/20)^2 - u^2) / (2 * -a)
S = 39u^2 / (800a)
For n planks
nS = u^2 / (2a)
n * 39u^2 / (800 a) = u^2 / (2a)
n = 400 / 39
n = 10.25
Minimum number of planks required to stop the bullet is 11
v = u - u/20 = 19u/20
For one plank
S = ((19u/20)^2 - u^2) / (2 * -a)
S = 39u^2 / (800a)
For n planks
nS = u^2 / (2a)
n * 39u^2 / (800 a) = u^2 / (2a)
n = 400 / 39
n = 10.25
Minimum number of planks required to stop the bullet is 11
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