Question

A bullet travels at a speed of 80 m s- whose mass is 0.018 kg and strikes the piece of wood whose mass is
0.6 kg and comes to rest instantly. By means of a thin wire, the block is suspended from the ceiling How high
does the block rise?​

Answer 1

Step-by-step explanation:

Given A bullet travels at a speed of 80 m s- whose mass is 0.018 kg and strikes the piece of wood whose mass is0.6 kg and comes to rest instantly. By means of a thin wire, the block is suspended from the ceiling How high  does the block rise?

• Mass of the bullet = 0.018 kg
• Initial speed will be = 80 m/s
• Mass of the wood = 0.6 kg
• Initial speed of the wood = 0
• Now we have the law of conservation of momentum,
•      m U1 +Mu2 = (m + M)v
•    (0.018 x 80) + (0.6 x 0) = (0.018 + 0.6)v
•      1.44 = 0.618 v
•     Or v = 2.33 m/s
• Now law of conservation of energy will be potential energy at high level = kinetic energy at low level.
•   So mgh = ½ mv^2
•      Or h = ½ v^2 / g
•               = ½ (2.33)^2 / 9.8
•                = 5.4289 / 19.6
•    Or h = 0.2769 m

Reference link will be

https://brainly.in/question/13548343

Answer 2

Answer:

H=0.2769m

Hope it helps you