A bus accelarets uniformly from 54km/h to 72 in 10second . Calculate
a) accelaration in m/s-2
b) distance travelled by the bus in meters during this interval
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(1) a=v-u/t
=72-54/t
=18/10
=1.8m/s
(2) s=ut+1/2a(t)^2
s=54*10+0.9*100
=540+90
=630
(1) a=v-u/t
=72-54/t
=18/10
=1.8m/s
(2) s=ut+1/2a(t)^2
s=54*10+0.9*100
=540+90
=630
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