Question

A bus accelerates uniformly form 54km/hr to 72km/hr in 10sec. calculate acceleration in km/hr and m/s ?​

Answer 1

Answer:

9/5 km/hr

1/2 m/s 2

Explanation:

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Answer 2

Given :

• Initial velocity (u) = 54 km/h
• Final velocity (v) = 72 km/h
• Time interval (t) = 10 seconds

To Find :

• Acceleration in km/h² and m/s²

Solution :

We're given that a bus changes its speed from 54 km/h to 72 km/h in 10 seconds.

So, for finding acceleration in km/h² we've to convert time into hours.

⇒Time = 10 seconds

⇒Time = 10/3600

⇒Time = 0.00278

$\therefore$ Time interval is 0.00278 hours

➠ a = v - u/t

⇒a = (72 - 54)/0.00278

⇒a = 6474.82 km/h²

$\therefore$ Acceleration in km/h is 6474.82 km/h²

_______________________________

Now, convert velocity to m/s by multiplying it by 5/18

• Initial velocity = 54 * 5/18 = 15
• Final velocity = 72 * 5/18 = 20
• Time (t) = 20 s

⇒a = v - u/t

⇒a = (20 - 15)/10

⇒a = 5/10

⇒a = 1/2

⇒a = 0.5

$\therefore$ Acceleration in m/s² is 0.5 m/s²