Question

a bus accelerates uniformly from 54 km per hour to 72 km per hour in 10 seconds calculate the distance covered by the bus in metres during interval and also find the acceleration in metre per second square

Answer 1

u=54km/h =54*5/18=15m/s.
v=72km/h=72*5/18=20m/s.
t=10s.
a=v-u/t.
a=20-15/10.
a=5/10.
a=1/5.
a=0.2m/s.
s=ut +at2/2.
s=150+20/2.
s=150+10.
s=160m.

Answer 2

Answer:

Explanation:

Given :-

Initial velocity, u = 72 km/h = 72 (5/18) m/s = 20 m/s  

Final velocity, v = 54 km/h = 54 (5/18) m/s = 15 m/s  

Time in which velocity changes is, t = 10 seconds  

To Find :-

(a) Acceleration

(b) Distance traveled

Formula to be used :-

a = (v - u)/t  and v² = u² + 2aS  

Solution :-

(a) Acceleration

Acceleration, a = (v - u)/t  

⇒ a = (20-15)/10

= 0.5 m/s²

(b) Distance traveled by the bus  

v² = u² + 2aS  

⇒ 20² = 15² + 2 × 0.5 × S  

⇒ 400 = 225 + 1×S

⇒ 400 - 225 = S

⇒ S = 175 m

Hence, the acceleration and distance traveled​ by bus is 0.5 m/s² and 175 m.

Same answer

Read more on Brainly.in - https://brainly.in/question/11360915#readmore