Question

A bus accelerates uniformly from 54km/hr to 72km/hr in 10 seconds Calculate(I) acceleration in m/s (ii) distance covered by the bus in meters during this interval

Answer 1

Answer:

the accelaration is 0.5 m/s^2

the distance is 175m.

Explanation:

you can use this formula to find accelaration:

v=u+at

you can use this formula to find distance:

s=ut+1/2at^2

or

2as+v^2 =u^2

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Answer 2

Answer:

(i) 0.5 m/s²

(ii) 175 metres

Explanation:

Given :

• Initial velocity = u = 54 km/hr

• Final velocity = v = 72 km/hr

• Time taken = t = 10 seconds

To find :

• Distance covered by the bus in metres during this interval

Initial velocity = 54×5/18 = 15 m/s

Final velocity = 72×5/18 = 20 m/s

Acceleration = (v-u)/t

Acceleration = (20-15)/10

Acceleration = 5/10

Acceleration = 0.5 m/s²

Using the second equation of motion :

S=u×t+½×at²

S=15×10+½×0.5×10²

S=150+25

S=175 metres

The distance covered by the bus during this interval is equal to 175 metres