Question

A bus accelerates uniformly from rest and acquires a speed of 36kmph in
10 s. The acceleration is​

Answer 1

Required Answer :

The acceleration of the bus = 1 m/s²

Given :

• Initial velocity of the bus = 0 m/s [Because it was initially at rest.]
• Final velocity of the bus = 36 km/h
• Time = 10 seconds

To find :

• Acceleration of the bus

Solution :

Here, we are given the initial velocity, final velocity and the time taken by the bus and we need to calculate the acceleration of the bus. To find the acceleration, we will be using the first equation of motion.

First equation of motion :

• v = u + at

where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time

we have,

• v = 36 km/h
• u = 0 m/s
• t = 10 seconds

The value of final velocity of the bus is in km/h, so firstly we will convert it to m/s.

To convert it in m/s mulitply the value by 5/18.

⇒ Final velocity = 36 × 5/18

⇒ Final velocity = 2 × 5

⇒ Final velocity = 10 m/s

Substituting the given values in first equation of motion :

⇒ 10 = 0 + (a)(10)

⇒ 10 = a × 10

⇒ 10/10 = a

⇒ 1 = a

Therefore, the acceleration of the bus = 1 m/s²