A bus acquires a velocity of 36 km/hr in 20 seconds just after the start. It takes 40 seconds to stop. Find the ratio of acceleration to retardation in these cases.
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Answer:
0.5/0.25 = 1/2 / 1/4
Explanation:
first find acceleration
a=vf-vi/t
= 36x10/36 - 0 / 20
= 10/20
= 1/2
then find deceleration
d=vf-vi/ t
= 0-36x10/36 / 40
= -10/40
= -1/4
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