A bus after start covers a distance of 200 m in 10 sec . Find the final velocity of the bus
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V = 40m/s Firstly by second equation of motion we will A Acceleration and then by first law of motion we will find V i.e final velocity....
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let the initial velocity be u.
final velocity (v)=Distance/time
=200/10
=20m s^-1
therefore v-u=at.
So a=v/t=20/10
=2 m s ^-2.
So,
20-u=2(10)
20-20=u.
u=0.
Therefore the initial velocity u =0 m s ^-1.
final velocity (v)=Distance/time
=200/10
=20m s^-1
therefore v-u=at.
So a=v/t=20/10
=2 m s ^-2.
So,
20-u=2(10)
20-20=u.
u=0.
Therefore the initial velocity u =0 m s ^-1.
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