Question

A bus at rest accelerated uniformly to a velocity of 54 km /h in 20 second .How much distance is covered by the bus in 20 second

Answer 1

Initial velocity (u) = 0 m/s

Final velocity (v) = 54 km/h = 15 m/s

Let the acceleration be a.

Time taken to achieve that speed = 20 seconds

Let the distance covered by the bus be s.

Now, using first equation of motion:

v = u + at

15 = 0 + a × 20

$a = \frac{15}{20}$

a = 0.75 m/s^2

Now, using the second equation of motion:

$s = ut + \frac{1}{2} \times a \times t^2$

$s = 0 + \frac{1}{2} \times 0.75 \times 20 \times 20$

s = 175 m

Hence, the distance covered by the bus is 175 m