Question

A bus B1, left a town T1 for another town T2 at 6:00 am at 7:30 am. Another bus B2 also left T1 for T2 and the speed of this bus was 5 km/h more than that of B1. At 10:30 pm, on the same day, the buses were 21 km apart. Find the speed of bus B

Answer 1

Answer:

Let Speed of B1 bus is  V    ;                time = 10:30-6:00=9/2 hrs

Speed of B2 bus would be V +5 ;       time = 10:30-7:30=3hrs

Distance between them = 21kms

Distance(B1)= Distance(B2)+ 21

(V)*9/2 = (V+5)*3 +21

After solving

Speed of A,(V=24); Speed of B (V+5)=29

Step-by-step explanation: