A bus begin to move with an acceleration of 1m/s^2. A boy who is 48m behind the bus starts running at 10m/s towards the bus. after what time bus will cross the boy??
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velocity of boy = 10 m/ss = 48 mAcceleration of man with respect to bus = Acceleration of bus - Acceleration of bus = 0 - (1) = -1 m/sApplying second equation of motion,s = ut + 1/2 at248 = 10t - 1/2*t2solving we get, t = 12 sec or t = 8 sectherefore the minimum time is 8 seconds
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