Question

A bus begin to move with an acceleration of 1ms-2. A man who is 48 m behind the bus starts running at 10ms-1 to catch the bus. The man will be able to catch the bus after what time​

Answer 1

Answer:

Let man will catch the bus after time t.Since the distance from man position is same for both at time t

⇒ Distance covered by bus = Distance covered by man -48

⇒21at2=vt−48

 ⇒21(1)t2=10t−48

⇒t2−20t+96=0

⇒(t−12)(t−8)=0

⇒t=8s (minimum value) or t=12s

So,at t=8s,the man will catch the bus

Explanation:

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