Question

A bus begins to move with an acceleration of 1 ms? a man who is 40 m
behind the bus starts running at 10 ms to catch the bus. The man will be able
to catch the bus after
(A) 6 s
(B) 5s (C)3s
(D) 75
(E) 8 S
(Kerala Engineering 2011)​

Answer 1

Answer:

Let man will catch the bus after time t.Since the distance from man position is same for both at time t

⇒ Distance covered by bus = Distance covered by man -48

⇒21at2=vt−48

 ⇒21(1)t2=10t−48

⇒t2−20t+96=0

⇒(t−12)(t−8)=0

⇒t=8s (minimum value) or t=12s

So,at t=8s,the man will catch the bus