Physics, asked by DeadlyXDemon, 10 months ago

A bus between visakhapatnam and Hyderabad passed the 100 km, 16 km and 220 km point at 10:30 pm ,11:30 pm and 10:30 pm . Find the average speed of the bus during each of the following intervals.
a. 10.30 am to 1.30 am
, b. 11.30 am to 1.30pm
, c.10.30 am to 1.30 pm​

Answers

Answered by Anonymous
52

Explanation:

(a) The distance covered between 10.30 a.m. and 11.30 a.m. is 160 km – 100 km = 60 km. The time interval is 1 hours.

The average speed during this interval is

Distance/time = 60km/ 1h

Distance = 60 km/h

(b) The distance covered between 11.30 a.m. and 1.30 p.m. is 220 km – 160 km = 60 km. The time interval is 2 hours. The average speed during this interval is

Distance/time = 60km / 2h

Distance = 30 km/h

(c) The distance covered between 10.30 a.m. and 1.30 p.m. is 220 km – 100 km = 120 km. The time interval is 3 hours. The average speed during this interval is

V3 = 120km/ {3h}= 40km/h....

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Answered by snehajangra2627
4

hii

v1 =60km/h

v2=30km/h

v3=40km/h

Explanation:

hope it helps you

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