A bus covers a certain distance in 60 minutes if it runs at a speed of 60 km/hr. What must be the speed of the bus in order to reduce the time of journey by 40 minutes?
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Step-by-step explanation:
Answer is 180km/hr.
It comes from the basic formula
S=d/t
S=speed
d=distance
t=time
In first case s=60km/hr which is constant till it completes the distance so acceleration is o. And it is rectilinear motion .hence we use simple one dimensional motion equation
S=d/t
First we calculate d
t=1hr.
d=s*t
d=60 km
Now again applying this but now t=20 min. i.e 1/3hr because time is reduced by 40 min.
So
S=60km*/(1/3)hr
S=180km/hr.
I hope this works!cheers.
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