a bus covers a distance A to B in three equal parts.In first part its speed is 60km/hr in 2nd 40km/hr and in last 50km/hr.At the time when Bus started from point A a car also started from point B and meet the bus after 4 hours in which car covered 400/9% distance.Find the speed of Car?
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"Total distance divided by total time is the total distance divided by the time in each direction:
(2AB)/ [(AB/40) + (AB/60)]
With common denominator of 2400, it works out to be:
(2AB)/[(60AB/2400) + (40AB/2400)]
Which becomes after combing terms in denominator:
(2AB)/[(100AB)/2400]
Invert and multiply:
[(2)(2400)AB]/(100AB)
Which is:
4800AB/100AB
After dividing, AB is cancelled out, and the number is:
48 is the average speed. this is the correct answer to the question given above."
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