Question

a bus covers a distance A to B in three equal parts.In first part its speed is 60km/hr in 2nd 40km/hr and in last 50km/hr.At the time when Bus started from point A a car also started from point B and meet the bus after 4 hours in which car covered 400/9% distance.Find the speed of Car?

Answer 1

Answer:

40 km/hr

Step-by-step explanation:

Let say Distance =  3D km

400/9% of 3D =  (400/900) * 3D = 4D/3

Distnace covered by car = 4D/3

Distnace covered by Bus = 3D - 4D/3 = 5D/3

Distance covered in 1st part by Bus = 3D/3 = D km

Speed = 60 km/Hr

Time taken = D/60 hr

Distance covered till Car & Bus meet in 2nd Part = 2D/3 km

Speed = 40 km/hr

Time Taken = (2D/3)/40 = D/60 hr

Total time taken by Bus = D/60 + D/60 = 2D/60 = D/30 hr

time taken by Bus= D/30 hr = Time taken by Car= 4 hr

=>  D = 120

Total Distance = 3D = 360 km

Distance  covered by Car = 4D/3 = 4 * 120/3 = 160 km

Speed of car = (160)/(4)  = 40 km/hr

Answer 2

Step-by-step explanation:

40 km/ kms

l hope so.l answered you