a bus covers a distance A to B in three equal parts.In first part its speed is 60km/hr in 2nd 40km/hr and in last 50km/hr.At the time when Bus started from point A a car also started from point B and meet the bus after 4 hours in which car covered 400/9% distance.Find the speed of Car?
Answers
Answer:
80 km/hr
Explanation:
Let assume Distance = 3D km
400/9% of 3D
= (400/900) * 3D
= 4D/3
Distance covered by car = 4D/3
Distance covered by Bus = 3D - 4D/3
= 5D/3
Distance covered in 1st part by Bus = 3D/3
= D km
Speed = 60 km/Hr
Time taken = D/60 hr
Distance covered till Car & Bus meet in 2nd Part = 2D/3 km
Speed = 40 km/hr
Time Taken = (2D/3)/40
= D/60 hr
Total time taken by Bus = D/60 + D/60
= 2D/60 = D/30 hr
time taken by Bus= D/30 hr
= Time taken by Car = 4 hr
=> D = 120
Total Distance = 3D = 360 km
Distance covered by Car = 4D/3
= 4 * 120/3 = 160 km
Speed of car = (160)/(4) = 40 km/hr