Question

a bus decrease it's speed from 72 kmhr-1 to 36kmh-1 in 1 min 40 sec find the acceleration of the bus​

Answer 1

Given :

Initial velocity of bus , u = 72 km/hr = 20 m/s

Final velocity of bus , v = 36km/hr = 10 m/s

Time interval , t = 1 min 40 sec = 100 sec

To Find :

Acceleration of the bus

Solution :

We have to find the acceleration of the bus

By First equation of motion

v = u + at

Put the given values

→ 10= 20+a×100

→ 100a = -10

→ a = $\frac{-10}{100}$

→a = -0.1 m/s²

Hence , Acceleration of the bus is -0.1 m/s²

Some important formula related to this topic :

Kinematic equations for uniformly accelerated motion.

1) v = u + at

2) S = ut +$\frac{1}{2}$at²

3) v²=u²+2aS

Answer 2

Answer:

Initial velocity of bus , u = 72 km/hr = 20 m/s

Final velocity of bus , v = 36km/hr = 10 m/s

Time interval , t = 1 min 40 sec = 100 sec

To Find :

Acceleration of the bus

Solution :

We have to find the acceleration of the bus

By First equation of motion

v = u + at

Put the given values

→ 10= 20+a×100

→ 100a = -10

→ a = \frac{-10}{100}

100

−10

→a = -0.1 m/s²

Hence , Acceleration of the bus is -0.1 m/s²

Some important formula related to this topic :

Kinematic equations for uniformly accelerated motion.

1) v = u + at

2) S = ut +\frac{1}{2}

2

1

at²

3) v²=u²+2aS