Question

A bus decrease its speed from 80 kilometre per hours to 60 kilometres per hour in 5 second find the acceleration of the bus .

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Answer 1

Answer:

u= initial velocity= 80 km/h = 22.2 m/s

v= final velocity = 60 km/h = 16.7 m/s

t= time = 5 s

a= acceleration = ?

a=v-u/t

a= 16.7-22.2/5

a= -5.5/5

Therefore, a=-1.1 m/s^2

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Answer 2

GIVEN :-

• Initial velocity (u) = 80 km/h
• Final velocity (v) = 60 km/h
• Time (t) = 5 sec

TO FIND :-

• The acceleration of the bus.

SOLUTION :-

➵ u = (80 × 1000)/3600 m/s

➵ u = 200/9 m/s

➵ v = (60 × 1000)/3600 m/s

➵ v = 50/3 m/s

Change in velocity,

⇒ Final velocity - Initial velocity

⇒ 50/3 - 200/9

⇒ (150 - 200)/9

⇒ -50/8 m/s

⇒ Acceleration = change in velocity/time

⇒ (-50/9)/5

⇒ -50/9 × 5

⇒-50/45

⇒ -10/9

⇒ -1.11 m/s²

Note :- (-) sign in the acceleration shows negative acceleration or retardation.