a bus decrease its speed from 80km/h to 60km/h in 10sec. find the acceleration of the bus. also find the distance covered by bus
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intial velocity =80km/h
final velocity =60km/h
time=10sec=10sec/120sec=(1/12)h
acceleration =v-u/t
=60km/h-80km/h/(1/12)h
=240km/h square
distance
s=ut+1/2at square
s=80×1/12+1/2×240×1/12×1/12
s=28.5 km
final velocity =60km/h
time=10sec=10sec/120sec=(1/12)h
acceleration =v-u/t
=60km/h-80km/h/(1/12)h
=240km/h square
distance
s=ut+1/2at square
s=80×1/12+1/2×240×1/12×1/12
s=28.5 km
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