Physics, asked by samruddha88, 1 year ago

See-saw of length 6 m is pivoted at its centre. A child (A) of mass 20kg is sitting on one end of the see saw. Where should another child B of mass 30kg. Sit, so that the see saw is balanced?
A. 1m
B. 1.5m
C. 2m
D. 2.5m

Answers

Answered by Anonymous
4
hey mate!

as mentioned in ques..

rod is pivoted at center. .
so it is 3cm on right side and remaning 3cn on left side...

apply..

m1x1 = m2x2

20 * 3 = x *30

60 =30 x

x =2cm

#Phoenix
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