A bus decreases its speed from 60 km/h to 40 km/h in 5 s find the acceleration of the bus.
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Answer:we know that,
From the first law of motion,
V=u+at
Here,v=60km/hr=60×5/18m/s=50/3m/s
u=40km/hr=40×5/18m/s=100/9m/s
t=5seconds
Apply these values in the above equation,
100/9=50/3+5a
20/9=10/3+a
a=20-30/9=-10/9
a=-1.11m/s²
So the bus is decelerating at the rate of-1.11m/s²...
Explanation:
Hope it helps you frnd.....
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