A bus decreases its speed from 72 km/h to 54 km/h in 10 sec.Calculate the acceleration of the bus.
Answers
Answered by
1
a = acceleration
v = final velocity
u = initial velocity
v-u/t = a
=18/10
=1.8m/s^2 (metre/second-square)
v = final velocity
u = initial velocity
v-u/t = a
=18/10
=1.8m/s^2 (metre/second-square)
Answered by
18
Hola
Answer -
Given - u = 72km/hr
v = 54km/hr
time = 10 seconds
To find - Acceleration
Calculation -
a = v - u / t
We need to convert km to m
thus,
we will multiply it by 5/18
72 × 5/18
4 × 5 => 20m
and
54 × 5/18
3 × 5 => 15m
a = 20 - 15 / 10
a = 5 / 10
a = 1/2 = 0.5m/s²
Answer -
Acceleration = 0.5m/s²
Hope it helps
Answer -
Given - u = 72km/hr
v = 54km/hr
time = 10 seconds
To find - Acceleration
Calculation -
a = v - u / t
We need to convert km to m
thus,
we will multiply it by 5/18
72 × 5/18
4 × 5 => 20m
and
54 × 5/18
3 × 5 => 15m
a = 20 - 15 / 10
a = 5 / 10
a = 1/2 = 0.5m/s²
Answer -
Acceleration = 0.5m/s²
Hope it helps
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