Redefine the function which is given by
f(x) = |x-1| + |x-3| , -6≤x≤6
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Answer:
f(x) = |x-1| + |x-3| , -6≤x≤6
critical points of x are 1 and 3
f(x) =
when x < 1 , -(x-1)-(x-3) = -x+1-x+3 = -2x + 4
when 1 ≤ x ≤ 3 , x-1-(x-3) = x-1-x+3 = 2
when x ≥ 3, x-1+x-3 = 2x - 4
Step-by-step explanation:
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