Math, asked by samantlucky4, 6 months ago

Redefine the function which is given by

f(x) = |x-1| + |x-3| , -6≤x≤6

Answers

Answered by poorveejain2004
0

Answer:

f(x) = |x-1| + |x-3| , -6≤x≤6

critical points of x are 1 and  3

f(x) =

when x < 1 , -(x-1)-(x-3) = -x+1-x+3 = -2x + 4

when 1 ≤ x ≤ 3 , x-1-(x-3) = x-1-x+3 = 2

when x ≥ 3, x-1+x-3 = 2x - 4

Step-by-step explanation:

Similar questions