a bus decreases its speed from 72 km per hour to 54 km per hour in 5 seconds find the acceleration of the bus
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39
Aceelerration = rate of change of velocity
= 72-54=18 km/hr =5 m/s
a=5/5=1 m/s
= 72-54=18 km/hr =5 m/s
a=5/5=1 m/s
khaibari:
derivation of sin root x in delta method
Answered by
27
decrease bus speed (72-54)km/hr
18km/hr
a = 5 m/s
acceleration of bus 5s
a = 5/5
a = 1 m/sec^2
18km/hr
a = 5 m/s
acceleration of bus 5s
a = 5/5
a = 1 m/sec^2
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