Chemistry, asked by 05689, 8 months ago

A bus decreases its speed from 80 km h−1 to 60 km h−1 in 5 s. Find the acceleration of the bus.

Answers

Answered by VishnuPriya2801
9

Answer:-

Given:

Initial Velocity of the bus (u) = 80 km/h => 80*5/18 = 22.22 m/s

Final Velocity of the bus (v) = 60 km/h => 60*5/18 = 16.6 m/s

Time = 5 s

We know that,

acceleration (a) = (v - u)/t

→ a = (16.6 - 22.2)/5

→ a = - 5.6/5

→ a = - 1.12 m/s²

Answered by llMichFabulousll
4

Explanation:

Answer: The acceleration of the bus that decreases its speed from 80 kilometers per hour to 60 km per hour in 5 seconds is -1.12m/s2

Let's look into the relationship between acceleration, speed and time

Explanation:

Acceleration a = (V - U) / t

Given: Initial velocity (U) = 80 km/hr = 80 × 5/18 = 400/18 = 22.2m/sec

Final velocity (V) = 60 km/hr = 60 × 5/18 = 300/18 = 16.6m/sec

Acceleration a = (V - U) / t

= (16.6 - 22.2)/5

= -5.6/5

= -1.12 m/s2

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