A bus decreases its speed from 80 km h−1 to 60 km h−1 in 5 s. Find the acceleration of the bus.
Answers
Answer:-
Given:
Initial Velocity of the bus (u) = 80 km/h => 80*5/18 = 22.22 m/s
Final Velocity of the bus (v) = 60 km/h => 60*5/18 = 16.6 m/s
Time = 5 s
We know that,
acceleration (a) = (v - u)/t
→ a = (16.6 - 22.2)/5
→ a = - 5.6/5
→ a = - 1.12 m/s²
Explanation:
Answer: The acceleration of the bus that decreases its speed from 80 kilometers per hour to 60 km per hour in 5 seconds is -1.12m/s2
Let's look into the relationship between acceleration, speed and time
Explanation:
Acceleration a = (V - U) / t
Given: Initial velocity (U) = 80 km/hr = 80 × 5/18 = 400/18 = 22.2m/sec
Final velocity (V) = 60 km/hr = 60 × 5/18 = 300/18 = 16.6m/sec
Acceleration a = (V - U) / t
= (16.6 - 22.2)/5
= -5.6/5
= -1.12 m/s2