Question

A bus decreases its speed from 80 km h-1 to 60 km h-1 in 5 s. Find the
acceleration of the bus.

Answer 1

Answer:

Given: Initial velocity (U) = 80 km/hr = 80 × 5/18 = 400/18 = 22.2m/sec

            Final velocity (V) = 60 km/hr = 60 × 5/18 = 300/18 = 16.6m/sec

Acceleration a = (V - U) / t

                        = (16.6 - 22.2)/5

                        = -5.6/5

                        = -1.12 m/s2

Negative sign indicates that the velocity is decreasing.

Explanation:

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Answer 2

Answer:

Here's your answer

Explanation:

Given => inital speed (u) = 80km/h = 22.2m/sec

               final speed (v) = 60km/h = 16.6m/sec

               time (t) = 5sec

               acceleration (a) = ?

By 1st equation of motion

v = u + a*t

16.6 = 22.5 + a*5

5a = 22.5-16.6

5a = -5.9

a = -5.9/5

a = -1.18m/sec (∵the bus is appline breakes hence the acceleration will be neagtive.)

Hope you understand.