Question

A bus decreases its speed from 80 km h^-1 to 6p km/hr^-1 in 5 sec. find the acceleration of the bus​

Answer 1

Answer:

hope you understand...

Explanation:

Initial speed u=80 km/h=80×

18

5

=22.22 m/s

Final speed v=60 km/h=60×

18

5

=16.67 m/s

Using v=u+at

Or 16.67=22.22+α×5

⟹ a=−1.1 m/s

2

Answer 2

Answer:

The acceleration of the bus is –1.1 m/s² (approx).

Explanation:

Given:

• Initial speed of the bus (u) = 80 km/h = 80 × 5/18 = 2.22 m/s.

• Final speed of the bus (v) = 60 m/hr⁻¹

= 60 × 5/18 = 16.66 m/s.

• Time taken (t) = 5 seconds.

To find:

Acceleration of the bus.

Solution:

We know that acceleration (a) = (v – u)/t

Now by substituting the known values, we get

a = (v – u)/t

⇒ a = (16.66 – 22.22)/5 = –1.1 m/s² (approx).