A bus decreases its speed from 80 Km/H to 60 km/h in 5 second find the acceleration and distance travelled by bus
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final speed,v=60kmph
initial speed,u=80kmph
time interval=5 seconds
acceleration=(v-u)÷t=(60-80)÷5= -20÷5= -4km/s^2
Negative sign here means retardation
v^2=u^2+ 2as
s=(60^2-80^2)÷(-4)×2
s=(3600-6400)÷(-8)
= -3600÷ -8
= 450km
initial speed,u=80kmph
time interval=5 seconds
acceleration=(v-u)÷t=(60-80)÷5= -20÷5= -4km/s^2
Negative sign here means retardation
v^2=u^2+ 2as
s=(60^2-80^2)÷(-4)×2
s=(3600-6400)÷(-8)
= -3600÷ -8
= 450km
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