Question

A bus decreases its speed from 80 km/h to 60 km/h in 5s find the acceleration of the bus​

Answer 1

Step-by-step explanation:

initial velocity ( u ) = 80 km/hr = 22.2 m/s

final velocity (v) = 60 km/hr = 16.6 m/s

time = 5 sec

acceleration = change in velocity/time taken

a = v-u / t

= 16.6-22.2/5

= -5.6/5

= -1.12 m/s^2

Answer 2

Answer:

★ $\fbox{\sf Acceleration = -1. 11\:m/s}$

Step-by-step explanation:

● Initial velocity (u) = 80 km/h

→ 22.22 m/s

● Final velocity (v) = 60 km/h

→ 16.66 m/s

● Time (t) = 5 seconds

★ $\fbox{\sf Acceleration : \dfrac{v - u}{t}}$

→ (16.66 - 22.22) m/s/5 s

→ - 1.11 m/s or -1.11 ms^-1

Know more:

※ There are three equations of motion :-

1. $\sf{v = u + at}$
2. $\sf{s = ut + \dfrac{1}{2}at^2}$
3. $\sf{2 as = u^2 - v^2}$

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