Question

a bus decreases its speed from 80 km/ hour to 5okm/ hour in 4 s ...find the acceleration of the bus​

Answer 1

Answer:

-7.5 km/hr(retardation)

Explanation:

u=80km/hr

v=50km/hr

t=4s

a = (v-u)/t

a = (50-80)/5

a = (-30)/4

a = -7.5km/hr (retardation)

Answer 2

$\large\bold{\underline{\sf{\blue{Given:–}}}}$

• Initial velocity of the bus u = 80 km/hr
• Final velocity of the bus v = 50 km/hr
• Time taken t = 4 seconds

$\large\bold{\underline{\sf{\blue{To\:find:–}}}}$

The acceleration of the bus = ?

$\large\bold{\underline{\sf{\blue{Solution:–}}}}$

Initial velocity = 80 km/hr = 22.22 m/s

Final velocity = 50 km/hr = 13.89 m/s

We know that,

$\boxed{\bf{\red{v=u+at}}}$

.°. 13.89 = 22.22 + a × 4 m/s²

⟹ 4a = 13.89 – 22.22 m/s²

⟹ 4a = –8.33 m/s²

⟹ a = – 2.083 (approximately)

Hence,the acceleration of the bus is –2.083 m/s²

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