A bus decreases its speed from 80 km per hour from 60 km per hour in 5 seconds calculate the acceleration of the bus
Answers
Answered by
2803
u= initial velocity= 80 km/h = 22.2 m/s
v= final velocity = 60 km/h = 16.7 m/s
t= time = 5 s
a= acceleration = ?
a=v-u/t
a= 16.7-22.2/5
a= -5.5/5
Therefore, a=-1.1 m/s^2
v= final velocity = 60 km/h = 16.7 m/s
t= time = 5 s
a= acceleration = ?
a=v-u/t
a= 16.7-22.2/5
a= -5.5/5
Therefore, a=-1.1 m/s^2
Answered by
12
Given: The initial speed of the bus, u = 80km
The final speed of the bus, v = 60 km
Time taken, t = 5s
To Find: acceleration of the bus, a.
Solution:
To calculate a, the formula used:
- v = u + a x t ⇒ First Law of Motion
or, it can be written as-
- a = v- u / t
Here, v-u = 60-80
= -20km/hr
Now covert, km/hr into m/s
1 km = 1000m
1 hr = 3600s
1 km/hr = 1000/3600
= 5/18 m/s
So, -20km/hr = -20x 5 / 18
= - 5.55 m/s
v- u = -5.55 m/s
Applying the formula for a :
a = -5.55 / 5
= -1.11m/s²
a = -1.11 m/s²
Negative sign shows that velocity of the bus is decreasing.
Hence, the acceleration of the bus is -1.11 m/s².
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