Question

A bus decreases its speed from 80km/h to 60km/h in 5s .Find the acceleration of the bus

Answer 1

Answer:

1.11 m/s^2

Explanation:

u=80 km/hr

v=60 km/hr

t=5

v-u = 20 km/hr=20*5/18=50/9 m/s

acc= (v-u)/t

= (50/9)/5

= 10/9 m/s^2

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Answer 2

$\textbf{\underline{\underline{According\:to\:the\:Question}}}$

★So know that :-

Change in velocity = (Final velocity - Initial velocity)

= 60 km/h - 80km/h

= -20 km/h

${\boxed{\sf\:{Convert\;it\; into\; m/s }}}$

$\tt{\rightarrow\dfrac{-20000m}{60\times 60s}}$

= -5.5 m/s

★Duration = 5 s

${\boxed{\sf\:{Formula\;of\; Acceleration}}}$

$\tt{\rightarrow a =\dfrac{Change\;in\;velocity}{Duration\;of\;time}}$

$\tt{\rightarrow\dfrac{-5.5}{5s}}$

= -1.1 m/s²

$\boxed{\begin{minipage}{11 cm} Additional Information \\ \\ \ Distance = Speed\times Time \\ \\ Displacement=Velocity\times time \\ \\ Average\; Speed = \dfrac{Initial\:\:Speed+Final\:\:Speed}{2} \end{minipage}}$